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प्रश्न
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
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उत्तर
`3/[ sqrt5 + sqrt2 ] xx ((sqrt5 - sqrt2)/(sqrt5 - sqrt2))`
= `[3 (sqrt5 - sqrt2)]/[ (sqrt5)^2 - (sqrt2)^2 ]`
= `[3 (sqrt5 - sqrt2)]/[ 5 - 2]`
= `sqrt5 - sqrt2`
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संबंधित प्रश्न
Rationalize the denominator.
`1/(3 sqrt 5 + 2 sqrt 2)`
Rationalise the denominators of : `3/sqrt5`
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Simplify :
` 22/[2sqrt3 + 1] + 17/[ 2sqrt3 - 1]`
Simplify by rationalising the denominator in the following.
`(7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)`
Simplify the following
`(3)/(5 - sqrt(3)) + (2)/(5 + sqrt(3)`
Simplify the following
`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`
Simplify the following :
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2)`
In the following, find the values of a and b:
`(sqrt(11) - sqrt(7))/(sqrt(11) + sqrt(7)) = "a" - "b"sqrt(77)`
Show that: `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2) = 11`
