Advertisements
Advertisements
Question
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
Advertisements
Solution
`3/[ sqrt5 + sqrt2 ] xx ((sqrt5 - sqrt2)/(sqrt5 - sqrt2))`
= `[3 (sqrt5 - sqrt2)]/[ (sqrt5)^2 - (sqrt2)^2 ]`
= `[3 (sqrt5 - sqrt2)]/[ 5 - 2]`
= `sqrt5 - sqrt2`
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`1/(sqrt 7 + sqrt 2)`
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
Rationalise the denominators of : `[ 2 - √3 ]/[ 2 + √3 ]`
Simplify by rationalising the denominator in the following.
`(3sqrt(2))/sqrt(5)`
Simplify by rationalising the denominator in the following.
`(sqrt(5) - sqrt(7))/sqrt(3)`
Simplify by rationalising the denominator in the following.
`(7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)`
In the following, find the value of a and b:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = "a" + "b"sqrt(5)`
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Show that: `x^3 + 1/x^3 = 52`, if x = 2 + `sqrt3`
Using the following figure, show that BD = `sqrtx`.
