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प्रश्न
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
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उत्तर
`3/[ sqrt5 + sqrt2 ] xx ((sqrt5 - sqrt2)/(sqrt5 - sqrt2))`
= `[3 (sqrt5 - sqrt2)]/[ (sqrt5)^2 - (sqrt2)^2 ]`
= `[3 (sqrt5 - sqrt2)]/[ 5 - 2]`
= `sqrt5 - sqrt2`
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संबंधित प्रश्न
Rationalise the denominators of : `[ 2 - √3 ]/[ 2 + √3 ]`
Simplify :
` 22/[2sqrt3 + 1] + 17/[ 2sqrt3 - 1]`
Simplify by rationalising the denominator in the following.
`(2)/(3 + sqrt(7)`
Simplify by rationalising the denominator in the following.
`(sqrt(3) + 1)/(sqrt(3) - 1)`
Simplify by rationalising the denominator in the following.
`(sqrt(15) + 3)/(sqrt(15) - 3)`
Simplify the following
`(sqrt(5) - 2)/(sqrt(5) + 2) - (sqrt(5) + 2)/(sqrt(5) - 2)`
Simplify the following :
`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`
In the following, find the value of a and b:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = "a" + "b"sqrt(5)`
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `(7 + 4sqrt(3))`, find the values of :
`(x + (1)/x)^2`
