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प्रश्न
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
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उत्तर
`3/[ sqrt5 + sqrt2 ] xx ((sqrt5 - sqrt2)/(sqrt5 - sqrt2))`
= `[3 (sqrt5 - sqrt2)]/[ (sqrt5)^2 - (sqrt2)^2 ]`
= `[3 (sqrt5 - sqrt2)]/[ 5 - 2]`
= `sqrt5 - sqrt2`
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संबंधित प्रश्न
Rationalize the denominator.
`1/sqrt5`
Rationalise the denominators of : `[ 2 - √3 ]/[ 2 + √3 ]`
Simplify :
` 22/[2sqrt3 + 1] + 17/[ 2sqrt3 - 1]`
Simplify by rationalising the denominator in the following.
`(4 + sqrt(8))/(4 - sqrt(8)`
Simplify the following :
`(6)/(2sqrt(3) - sqrt(6)) + sqrt(6)/(sqrt(3) + sqrt(2)) - (4sqrt(3))/(sqrt(6) - sqrt(2)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
In the following, find the values of a and b:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = "a" - "b"sqrt(6)`
In the following, find the value of a and b:
`(sqrt(3) - 1)/(sqrt(3) + 1) + (sqrt(3) + 1)/(sqrt(3) - 1) = "a" + "b"sqrt(3)`
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Show that:
`(4 - sqrt5)/(4 + sqrt5) + 2/(5 + sqrt3) + (4 + sqrt5)/(4 - sqrt5) + 2/(5 - sqrt3) = 52/11`
