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प्रश्न
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
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उत्तर
`3/[ sqrt5 + sqrt2 ] xx ((sqrt5 - sqrt2)/(sqrt5 - sqrt2))`
= `[3 (sqrt5 - sqrt2)]/[ (sqrt5)^2 - (sqrt2)^2 ]`
= `[3 (sqrt5 - sqrt2)]/[ 5 - 2]`
= `sqrt5 - sqrt2`
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संबंधित प्रश्न
Rationalize the denominator.
`4/(7+ 4 sqrt3)`
Simplify by rationalising the denominator in the following.
`(3 - sqrt(3))/(2 + sqrt(2)`
Simplify the following
`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`
In the following, find the value of a and b:
`(sqrt(3) - 1)/(sqrt(3) + 1) + (sqrt(3) + 1)/(sqrt(3) - 1) = "a" + "b"sqrt(3)`
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `(7 + 4sqrt(3))`, find the value of `x^3 + (1)/x^3`.
If x = `(4 - sqrt(15))`, find the values of
`x + (1)/x`
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Simplify:
`(sqrt(x^2 + y^2) - y)/(x - sqrt(x^2 - y^2)) ÷ (sqrt(x^2 - y^2) + x)/(sqrt(x^2 + y^2) + y)`
Show that: `x^3 + 1/x^3 = 52`, if x = 2 + `sqrt3`
