Advertisements
Advertisements
प्रश्न
Rationalize the denominator.
`1/sqrt5`
Advertisements
उत्तर
`1/sqrt5 = 1/sqrt5 xx sqrt 5/ sqrt 5 ...["multiply numerator and denominator by" sqrt5]`
`= sqrt 5/5`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`1/(3 sqrt 5 + 2 sqrt 2)`
Rationalize the denominator.
`12/(4sqrt3 - sqrt 2)`
Rationalise the denominators of:
`[sqrt6 - sqrt5]/[sqrt6 + sqrt5]`
Simplify:
`sqrt2/[sqrt6 - sqrt2] - sqrt3/[sqrt6 + sqrt2]`
Simplify by rationalising the denominator in the following.
`(3sqrt(2))/sqrt(5)`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify by rationalising the denominator in the following.
`(5 + sqrt(6))/(5 - sqrt(6)`
Simplify by rationalising the denominator in the following.
`(sqrt(7) - sqrt(5))/(sqrt(7) + sqrt(5)`
Simplify by rationalising the denominator in the following.
`(2sqrt(3) - sqrt(6))/(2sqrt(3) + sqrt(6)`
Simplify by rationalising the denominator in the following.
`(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6)`
Simplify the following
`(sqrt(5) - 2)/(sqrt(5) + 2) - (sqrt(5) + 2)/(sqrt(5) - 2)`
In the following, find the values of a and b.
`(sqrt(3) - 1)/(sqrt(3) + 1) = "a" + "b"sqrt(3)`
In the following, find the values of a and b:
`(sqrt(11) - sqrt(7))/(sqrt(11) + sqrt(7)) = "a" - "b"sqrt(77)`
If x = `(4 - sqrt(15))`, find the values of:
`(x + (1)/x)^2`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of
x2 - y2 + xy
Show that: `x^3 + 1/x^3 = 52`, if x = 2 + `sqrt3`
Show that: `x^2 + 1/x^2 = 34,` if x = 3 + `2sqrt2`
Show that: `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2) = 11`
