Advertisements
Advertisements
प्रश्न
Rationalise the denominators of : `[ 2 - √3 ]/[ 2 + √3 ]`
Advertisements
उत्तर
`[ 2 - √3 ]/[ 2 + √3 ] xx [ 2 - √3 ]/[ 2 - √3 ]`
= `[( 2 - √3 )^2]/[(2)^2 - (√3)^2] = [ 4 + 3 - 4√3]/[ 4 - 3 ]`
= `[ 7 - 4√3 ]/1`
= 7 - 4√3
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`1/sqrt5`
Rationalize the denominator.
`2/(3 sqrt 7)`
Rationalize the denominator.
`1/(3 sqrt 5 + 2 sqrt 2)`
Simplify by rationalising the denominator in the following.
`(1)/(sqrt(3) + sqrt(2))`
Simplify the following
`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`
In the following, find the values of a and b:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = "a" + "b"sqrt(3)`
In the following, find the value of a and b:
`(sqrt(3) - 1)/(sqrt(3) + 1) + (sqrt(3) + 1)/(sqrt(3) - 1) = "a" + "b"sqrt(3)`
Evaluate, correct to one place of decimal, the expression `5/(sqrt20 - sqrt10)`, if `sqrt5` = 2.2 and `sqrt10` = 3.2.
Draw a line segment of length `sqrt5` cm.
Using the following figure, show that BD = `sqrtx`.

