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प्रश्न
Draw a line segment of length `sqrt5` cm.
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उत्तर
Construct a right-angled triangel OAB with
OA = 2 cm,
∠OAB = 90° and
AB = 1 cm
Using OB2 = OA2 + AB2
OB2 = 22 + 12
OB2 = 4 + 1
OB2 = 5
OB = `sqrt5`
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संबंधित प्रश्न
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify by rationalising the denominator in the following.
`(5 + sqrt(6))/(5 - sqrt(6)`
In the following, find the values of a and b:
`(3 + sqrt(7))/(3 - sqrt(7)) = "a" + "b"sqrt(7)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
In the following, find the values of a and b:
`(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)) = "a" - "b"sqrt(6)`
If x = `(4 - sqrt(15))`, find the values of
`x^3 + (1)/x^3`
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x2 + y2
Simplify:
`(sqrt(x^2 + y^2) - y)/(x - sqrt(x^2 - y^2)) ÷ (sqrt(x^2 - y^2) + x)/(sqrt(x^2 + y^2) + y)`
