Advertisements
Advertisements
Question
Draw a line segment of length `sqrt5` cm.
Advertisements
Solution
Construct a right-angled triangel OAB with

OA = 2 cm,
∠OAB = 90° and
AB = 1 cm
Using OB2 = OA2 + AB2
OB2 = 22 + 12
OB2 = 4 + 1
OB2 = 5
OB = `sqrt5`

APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`4/(7+ 4 sqrt3)`
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Simplify : `sqrt18/[ 5sqrt18 + 3sqrt72 - 2sqrt162]`
Simplify by rationalising the denominator in the following.
`(1)/(sqrt(3) + sqrt(2))`
Simplify the following
`(3)/(5 - sqrt(3)) + (2)/(5 + sqrt(3)`
Simplify the following
`(4 + sqrt(5))/(4 - sqrt(5)) + (4 - sqrt(5))/(4 + sqrt(5)`
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Show that Negative of an irrational number is irrational.
Show that: `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2) = 11`
