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प्रश्न
Draw a line segment of length `sqrt5` cm.
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उत्तर
Construct a right-angled triangel OAB with
OA = 2 cm,
∠OAB = 90° and
AB = 1 cm
Using OB2 = OA2 + AB2
OB2 = 22 + 12
OB2 = 4 + 1
OB2 = 5
OB = `sqrt5`
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संबंधित प्रश्न
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
Rationalize the denominator.
`1/(3 sqrt 5 + 2 sqrt 2)`
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Simplify by rationalising the denominator in the following.
`(3sqrt(2))/sqrt(5)`
Simplify by rationalising the denominator in the following.
`(1)/(sqrt(3) + sqrt(2))`
Simplify the following :
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2)`
If `(sqrt(2.5) - sqrt(0.75))/(sqrt(2.5) + sqrt(0.75)) = "p" + "q"sqrt(30)`, find the values of p and q.
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x2 + y2
Draw a line segment of length `sqrt3` cm.
Show that: `x^3 + 1/x^3 = 52`, if x = 2 + `sqrt3`
