Advertisements
Advertisements
प्रश्न
If x = `(4 - sqrt(15))`, find the values of
`(1)/x`
Advertisements
उत्तर
`(1)/x`
`(1)/x = (1)/((4 - sqrt(15))`
= `(1)/((4 - sqrt(15))) xx ((4 + sqrt(15)))/((4 + sqrt(15))`
= `((4 + sqrt(15)))/(16 - 15)`
= `(4 + sqrt(15))`
APPEARS IN
संबंधित प्रश्न
Rationalise the denominators of : `[ √3 + 1 ]/[ √3 - 1 ]`
Simplify the following :
`(6)/(2sqrt(3) - sqrt(6)) + sqrt(6)/(sqrt(3) + sqrt(2)) - (4sqrt(3))/(sqrt(6) - sqrt(2)`
Simplify the following :
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2)`
Simplify the following :
`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `(4 - sqrt(15))`, find the values of:
`(x + (1)/x)^2`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of
x2 - y2 + xy
Simplify:
`(sqrt(x^2 + y^2) - y)/(x - sqrt(x^2 - y^2)) ÷ (sqrt(x^2 - y^2) + x)/(sqrt(x^2 + y^2) + y)`
Show that: `x^2 + 1/x^2 = 34,` if x = 3 + `2sqrt2`
Using the following figure, show that BD = `sqrtx`.

