Advertisements
Advertisements
प्रश्न
Simplify the following :
`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`
Advertisements
उत्तर
`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`
Rationalizing the denominator of each term, we have
= `(4sqrt(3)(2 + sqrt(2)))/((2 - sqrt(2))(2 + sqrt(2))) - (30(4sqrt(3) + 3sqrt(2)))/((4sqrt(3) - 3sqrt(2))(4sqrt(3) + 3sqrt(2))) - (3sqrt(2)(3 - 2sqrt(3)))/((3 + 2sqrt(3))(3 - 2sqrt(3))`
= `(8sqrt(3) + 4sqrt(6))/(4 - 2) - (120sqrt(3) + 90sqrt(2))/(48 - 18) - (9sqrt(2) - 6sqrt(6))/(9 - 12)`
= `(8sqrt(3) + 4sqrt(6))/(2) - (120sqrt(3) + 90sqrt(2))/(30) - (9sqrt(2) - 6sqrt(6))/(-3)`
= `(8sqrt(3) + 4sqrt(6))/(2) - (120sqrt(3) + 90sqrt(2))/(30) - (9sqrt(2) - 6sqrt(6))/(3)`
= `4sqrt(3) + 2sqrt(6) - 4sqrt(3) - 3sqrt(2) + 3sqrt(2) - 2sqrt(6)`
= 0
APPEARS IN
संबंधित प्रश्न
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Simplify by rationalising the denominator in the following.
`(1)/(5 + sqrt(2))`
Simplify by rationalising the denominator in the following.
`(3 - sqrt(3))/(2 + sqrt(2)`
Simplify the following
`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`
In the following, find the values of a and b:
`(3 + sqrt(7))/(3 - sqrt(7)) = "a" + "b"sqrt(7)`
In the following, find the values of a and b:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = "a" - "b"sqrt(6)`
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of
x2 - y2 + xy
Using the following figure, show that BD = `sqrtx`.

