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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ९ वी

Rationalize the Denominator. 2/(3 sqrt 7)

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प्रश्न

Rationalize the denominator.

`2/(3 sqrt 7)`

बेरीज
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उत्तर

`2/(3 sqrt 7)`

`= 2/(3 sqrt 7) xx sqrt 7/sqrt7`   ...[multiply numerator and denominator by `sqrt7`]

`= (2sqrt7)/(3 xx 7)`

`= (2sqrt 7)/21`

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Simplifying an Expression by Rationalization of the Denominator
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पाठ 2: Real Numbers - Problem Set 2 [पृष्ठ ३५]

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बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
पाठ 2 Real Numbers
Problem Set 2 | Q (8) (ii) | पृष्ठ ३५

संबंधित प्रश्‍न

Rationalize the denominator.

`1/sqrt5`


Rationalize the denominator.

`12/(4sqrt3 - sqrt 2)`


Rationalise the denominators of : `3/sqrt5`


Rationalise the denominators of : `1/(sqrt3 - sqrt2 )`


Rationalise the denominators of : `[ 2 - √3 ]/[ 2 + √3 ]`


Simplify by rationalising the denominator in the following.

`(1)/(5 + sqrt(2))`


Simplify by rationalising the denominator in the following.

`(sqrt(5) - sqrt(7))/sqrt(3)`


Simplify by rationalising the denominator in the following.

`(3 - sqrt(3))/(2 + sqrt(2)`


Simplify by rationalising the denominator in the following.

`(2sqrt(3) - sqrt(6))/(2sqrt(3) + sqrt(6)`


Simplify the following

`(sqrt(5) - 2)/(sqrt(5) + 2) - (sqrt(5) + 2)/(sqrt(5) - 2)`


Simplify the following

`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`


Simplify the following

`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`


Simplify the following :

`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`


In the following, find the values of a and b.

`(sqrt(3) - 1)/(sqrt(3) + 1) = "a" + "b"sqrt(3)`


In the following, find the values of a and b:

`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`


In the following, find the value of a and b:

`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = "a" + "b"sqrt(5)`


In the following, find the value of a and b:

`(sqrt(3) - 1)/(sqrt(3) + 1) + (sqrt(3) + 1)/(sqrt(3) - 1) = "a" + "b"sqrt(3)`


If x = `(7 + 4sqrt(3))`, find the value of

`sqrt(x) + (1)/(sqrt(x)`


If x = `(4 - sqrt(15))`, find the values of 

`(1)/x`


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