Advertisements
Advertisements
प्रश्न
Simplify by rationalising the denominator in the following.
`(3 - sqrt(3))/(2 + sqrt(2)`
Advertisements
उत्तर
`(3 - sqrt(3))/(2 + sqrt(2)`
= `(3 - sqrt(3))/(2 + sqrt(2)) xx (2 - sqrt(2))/(2 - sqrt(2)`
= `(3(2 - sqrt(2)) - sqrt(3)(2 - sqrt(2)))/((2)^2 - (sqrt(2))^2)`
= `(6 - 3sqrt(2) - 2sqrt(3) + sqrt(6))/(4 - 2)`
= `(6 - 3sqrt(2) - 2sqrt(3) + sqrt(6))/(2)`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`3/(2 sqrt 5 - 3 sqrt 2)`
Rationalise the denominators of : `3/sqrt5`
Rationalise the denominators of : `[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ]`
Simplify by rationalising the denominator in the following.
`(1)/(5 + sqrt(2))`
Simplify by rationalising the denominator in the following.
`(1)/(sqrt(3) + sqrt(2))`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify the following
`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
If x = `(4 - sqrt(15))`, find the values of
`x + (1)/x`
If x = `sqrt3 - sqrt2`, find the value of:
(i) `x + 1/x`
(ii) `x^2 + 1/x^2`
(iii) `x^3 + 1/x^3`
(iv) `x^3 + 1/x^3 - 3(x^2 + 1/x^2) + x + 1/x`
