मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ९ वी

Rationalize the denominator. 12/(4sqrt3 - sqrt 2) - Algebra

Advertisements
Advertisements

प्रश्न

Rationalize the denominator.

`12/(4sqrt3 - sqrt 2)`

बेरीज
Advertisements

उत्तर

`12/(4sqrt3 - sqrt 2)`

`= 12/(4sqrt3 - sqrt 2) xx  (4sqrt3 + sqrt 2)/(4sqrt3 + sqrt 2)`

`= (12 (4sqrt3 + sqrt 2))/((4sqrt3)^2 -(sqrt 2)^2)   ...[(a+b)(a-b) = a^2 - b^2]`

`=(12 (4sqrt3 + sqrt 2))/(48 - 2)`

`= (12 (4sqrt3 + sqrt 2))/46`

`= (6 (4sqrt3 + sqrt 2))/23`

shaalaa.com
Simplifying an Expression by Rationalization of the Denominator
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Real Numbers - Problem Set 2 [पृष्ठ ३५]

APPEARS IN

बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
पाठ 2 Real Numbers
Problem Set 2 | Q (8) (v) | पृष्ठ ३५

संबंधित प्रश्‍न

Rationalize the denominator.

`1/(sqrt 3 - sqrt 2)`


Rationalise the denominators of : `3/sqrt5`


Rationalise the denominators of : `(2sqrt3)/sqrt5`


Rationalise the denominators of : `1/(sqrt3 - sqrt2 )`


Rationalise the denominator of `1/[ √3 - √2 + 1]`


Simplify by rationalising the denominator in the following.

`(5)/(sqrt(7) - sqrt(2))`


Simplify by rationalising the denominator in the following.

`(42)/(2sqrt(3) + 3sqrt(2)`


Simplify by rationalising the denominator in the following.

`(7sqrt(3) -  5sqrt(2))/(sqrt(48) + sqrt(18)`


Simplify the following

`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`


Simplify the following

`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`


Simplify the following :

`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2)`


In the following, find the values of a and b.

`(sqrt(3) - 1)/(sqrt(3) + 1) = "a" + "b"sqrt(3)`


In the following, find the values of a and b:

`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = "a" + "b"sqrt(3)`


In the following, find the values of a and b:

`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`


In the following, find the values of a and b:

`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`


If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of 

x3 + y3


If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of 

x2 - y2 + xy


Draw a line segment of length `sqrt8` cm.


Using the following figure, show that BD = `sqrtx`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×