Advertisements
Advertisements
प्रश्न
Rationalize the denominator.
`1/(sqrt 7 + sqrt 2)`
Advertisements
उत्तर
`1/(sqrt 7 + sqrt 2)`
`= 1/(sqrt 7 + sqrt 2) xx (sqrt 7 - sqrt 2)/(sqrt 7 - sqrt 2)`
`= (sqrt 7 - sqrt 2)/((sqrt 7)^2 - (sqrt 2)^2)` ....`[(a + b)(a - b) = a^2- b^2]`
`= (sqrt 7 - sqrt 2)/(7-2)`
`= (sqrt 7 - sqrt 2)/5`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`1/sqrt5`
Rationalize the denominator.
`1/(sqrt 3 - sqrt 2)`
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
Simplify:
`sqrt2/[sqrt6 - sqrt2] - sqrt3/[sqrt6 + sqrt2]`
If `sqrt2` = 1.4 and `sqrt3` = 1.7, find the value of `(2 - sqrt3)/(sqrt3).`
Simplify by rationalising the denominator in the following.
`(42)/(2sqrt(3) + 3sqrt(2)`
Simplify by rationalising the denominator in the following.
`(5 + sqrt(6))/(5 - sqrt(6)`
Simplify by rationalising the denominator in the following.
`(7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)`
Simplify the following :
`(7sqrt(3))/(sqrt(10) + sqrt(3)) - (2sqrt(5))/(sqrt(6) + sqrt(5)) - (3sqrt(2))/(sqrt(15) + 3sqrt(2)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
In the following, find the values of a and b:
`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`
In the following, find the values of a and b:
`(sqrt(11) - sqrt(7))/(sqrt(11) + sqrt(7)) = "a" - "b"sqrt(77)`
If x = `(4 - sqrt(15))`, find the values of
`(1)/x`
If x = `(4 - sqrt(15))`, find the values of
`x + (1)/x`
If x = `(4 - sqrt(15))`, find the values of
`x^3 + (1)/x^3`
If x = `(4 - sqrt(15))`, find the values of:
`(x + (1)/x)^2`
If x = `((2 + sqrt(5)))/((2 - sqrt(5))` and y = `((2 - sqrt(5)))/((2 + sqrt(5))`, show that (x2 - y2) = `144sqrt(5)`.
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x2 + y2
Using the following figure, show that BD = `sqrtx`.

