Advertisements
Advertisements
प्रश्न
Rationalize the denominator.
`1/(sqrt 7 + sqrt 2)`
Advertisements
उत्तर
`1/(sqrt 7 + sqrt 2)`
`= 1/(sqrt 7 + sqrt 2) xx (sqrt 7 - sqrt 2)/(sqrt 7 - sqrt 2)`
`= (sqrt 7 - sqrt 2)/((sqrt 7)^2 - (sqrt 2)^2)` ....`[(a + b)(a - b) = a^2- b^2]`
`= (sqrt 7 - sqrt 2)/(7-2)`
`= (sqrt 7 - sqrt 2)/5`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
Rationalise the denominators of : `3/sqrt5`
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Rationalise the denominator of `1/[ √3 - √2 + 1]`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify by rationalising the denominator in the following.
`(4 + sqrt(8))/(4 - sqrt(8)`
Simplify by rationalising the denominator in the following.
`(sqrt(7) - sqrt(5))/(sqrt(7) + sqrt(5)`
Simplify the following
`(sqrt(5) - 2)/(sqrt(5) + 2) - (sqrt(5) + 2)/(sqrt(5) - 2)`
Simplify the following :
`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`
In the following, find the values of a and b:
`(3 + sqrt(7))/(3 - sqrt(7)) = "a" + "b"sqrt(7)`
In the following, find the values of a and b:
`(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)) = "a" - "b"sqrt(6)`
If x = `(7 + 4sqrt(3))`, find the values of :
`(x + (1)/x)^2`
If x = `(4 - sqrt(15))`, find the values of
`x^2 + (1)/x^2`
If x = `(4 - sqrt(15))`, find the values of:
`(x + (1)/x)^2`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x3 + y3
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) - 1)`, find the values of
x2 - y2 + xy
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
