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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता ९ वी

Rationalize the denominator. (sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)

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प्रश्न

Rationalize the denominator.

`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`

बेरीज
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उत्तर

`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`

`= (sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3) xx (sqrt 5 - sqrt 3)/(sqrt 5 - sqrt 3)`

`= (sqrt 5 - sqrt 3)^2/((sqrt 5)^2 - (sqrt 3)^2)     ....[because (a + b)(a - b) = a^2 - b^2]`

`= ((sqrt 5)^2 - 2(sqrt 5)(sqrt 3) + (sqrt 3)^2)/(5-3)   ...[because (a - b)^2 = a^2 - 2ab + b^2]`

`= (5 - 2sqrt15 + 3 )/2`

`= (8 - 2sqrt 15)/2`

`= (2 (4 - sqrt15))/2`

`= 4 -sqrt15`

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Simplifying an Expression by Rationalization of the Denominator
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Real Numbers - Practice Set 2.4 [पृष्ठ ३२]

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बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
पाठ 2 Real Numbers
Practice Set 2.4 | Q (2) (iv) | पृष्ठ ३२

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`2/(3 sqrt 7)`


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`(42)/(2sqrt(3) + 3sqrt(2)`


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`(sqrt(5) - sqrt(7))/sqrt(3)`


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`(7sqrt(3) -  5sqrt(2))/(sqrt(48) + sqrt(18)`


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`(3)/(5 - sqrt(3)) + (2)/(5 + sqrt(3)`


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`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`


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`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = "a" - "b"sqrt(6)`


If x = `(7 + 4sqrt(3))`, find the value of

`x^2 + (1)/x^2`


If x = `(7 + 4sqrt(3))`, find the value of `x^3 + (1)/x^3`.


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`(4 - sqrt5)/(4 + sqrt5) + 2/(5 + sqrt3) + (4 + sqrt5)/(4 - sqrt5) + 2/(5 - sqrt3) = 52/11`


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