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प्रश्न
Simplify by rationalising the denominator in the following.
`(5sqrt(3) - sqrt(15))/(5sqrt(3) + sqrt(15)`
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उत्तर
`(5sqrt(3) - sqrt(15))/(5sqrt(3) + sqrt(15)`
= `(5sqrt(3) - sqrt(15))/(5sqrt(3) + sqrt(15)) xx (5sqrt(3) - sqrt(15))/(5sqrt(3) - sqrt(15)`
= `((5sqrt(3) - sqrt(15))^2)/((5sqrt(3))^2 - (sqrt(15))^2`
= `(75 + 15 - 10sqrt(45))/(75 - 15)`
= `(90 - 10sqrt(45))/(60)`
= `(9 - 1sqrt(45))/(6)`
= `(9 - 3sqrt(5))/(6)`
= `(3 - sqrt(5))/(2)`
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संबंधित प्रश्न
Rationalize the denominator.
`4/(7+ 4 sqrt3)`
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
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`12/(4sqrt3 - sqrt 2)`
Simplify :
` 22/[2sqrt3 + 1] + 17/[ 2sqrt3 - 1]`
Simplify by rationalising the denominator in the following.
`(3sqrt(2))/sqrt(5)`
Simplify by rationalising the denominator in the following.
`(4 + sqrt(8))/(4 - sqrt(8)`
Simplify by rationalising the denominator in the following.
`(2sqrt(3) - sqrt(6))/(2sqrt(3) + sqrt(6)`
Simplify the following
`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`
In the following, find the values of a and b.
`(sqrt(3) - 1)/(sqrt(3) + 1) = "a" + "b"sqrt(3)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
