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प्रश्न
Rationalise the denominators of : `[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ]`
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उत्तर
`[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ] xx [ sqrt3 - sqrt2 ]/[ sqrt3 - sqrt2 ]`
= ` (sqrt3 - sqrt2 )^2/[(sqrt3)^2 - (sqrt2)^2]`
= `[ 3 + 2 - 2sqrt6 ]/[ 3 - 2 ]`
= 5 - 2√6
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संबंधित प्रश्न
Rationalize the denominator.
`3/(2 sqrt 5 - 3 sqrt 2)`
Rationalize the denominator.
`1/(sqrt 3 - sqrt 2)`
Rationalise the denominators of : `1/(sqrt3 - sqrt2 )`
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify by rationalising the denominator in the following.
`(sqrt(15) + 3)/(sqrt(15) - 3)`
Simplify by rationalising the denominator in the following.
`(2sqrt(3) - sqrt(6))/(2sqrt(3) + sqrt(6)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
In the following, find the values of a and b:
`(sqrt(11) - sqrt(7))/(sqrt(11) + sqrt(7)) = "a" - "b"sqrt(77)`
Show that:
`(4 - sqrt5)/(4 + sqrt5) + 2/(5 + sqrt3) + (4 + sqrt5)/(4 - sqrt5) + 2/(5 - sqrt3) = 52/11`
