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प्रश्न
Rationalise the denominators of : `[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ]`
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उत्तर
`[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ] xx [ sqrt3 - sqrt2 ]/[ sqrt3 - sqrt2 ]`
= ` (sqrt3 - sqrt2 )^2/[(sqrt3)^2 - (sqrt2)^2]`
= `[ 3 + 2 - 2sqrt6 ]/[ 3 - 2 ]`
= 5 - 2√6
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संबंधित प्रश्न
Rationalize the denominator.
`1/sqrt5`
Simplify :
` 22/[2sqrt3 + 1] + 17/[ 2sqrt3 - 1]`
Simplify by rationalising the denominator in the following.
`(sqrt(5) - sqrt(7))/sqrt(3)`
Simplify by rationalising the denominator in the following.
`(3 - sqrt(3))/(2 + sqrt(2)`
Simplify by rationalising the denominator in the following.
`(4 + sqrt(8))/(4 - sqrt(8)`
Simplify the following :
`sqrt(6)/(sqrt(2) + sqrt(3)) + (3sqrt(2))/(sqrt(6) + sqrt(3)) - (4sqrt(3))/(sqrt(6) + sqrt(2)`
In the following, find the values of a and b:
`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = "a" + "b"sqrt(3)`
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `(4 - sqrt(15))`, find the values of
`x + (1)/x`
Show that:
`(4 - sqrt5)/(4 + sqrt5) + 2/(5 + sqrt3) + (4 + sqrt5)/(4 - sqrt5) + 2/(5 - sqrt3) = 52/11`
