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प्रश्न
Simplify by rationalising the denominator in the following.
`(5 + sqrt(6))/(5 - sqrt(6)`
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उत्तर
`(5 + sqrt(6))/(5 - sqrt(6)`
= `(5 + sqrt(6))/(5 - sqrt(6)) xx (5 + sqrt(6))/(5 + sqrt(6)`
= `((5 + sqrt(6))^2)/((5)^2 - (sqrt(6))^2`
= `(25 + 6 + 10sqrt(6))/(25 - 6)`
= `(31 + 10sqrt(6))/(19)`
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संबंधित प्रश्न
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In the following, find the values of a and b:
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Using the following figure, show that BD = `sqrtx`.

