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Rationalize the denominator. 325-32 - Algebra

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प्रश्न

Rationalize the denominator.

`3/(2 sqrt 5 - 3 sqrt 2)`

योग
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उत्तर

`3/(2 sqrt 5 - 3 sqrt 2)`

`= 3/(2 sqrt 5 - 3 sqrt 2) xx (2 sqrt 5 + 3 sqrt 2)/(2 sqrt 5 + 3 sqrt 2)` 

`= (3(2 sqrt 5 + 3 sqrt 2))/((2 sqrt 5)^2 - (3 sqrt 2)^2)`

.....`[("a" + "b")("a" - "b") = "a"^2 - "b"^2]`

`= (3(2 sqrt 5 + 3 sqrt 2))/(4 xx 5 - 9 xx 2)`

`= (3(2 sqrt 5 + 3 sqrt 2))/(20 - 18)`

`= (3(2 sqrt 5 + 3 sqrt 2))/2`

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Simplifying an Expression by Rationalization of the Denominator
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Real Numbers - Practice Set 2.4 [पृष्ठ ३२]

APPEARS IN

बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
अध्याय 2 Real Numbers
Practice Set 2.4 | Q (2) (ii) | पृष्ठ ३२

संबंधित प्रश्न

Rationalize the denominator.

`1/(sqrt 7 + sqrt 2)` 


Rationalize the denominator.

`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`


Rationalise the denominators of : `3/sqrt5`


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Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`


Simplify by rationalising the denominator in the following.

`(1)/(sqrt(3) + sqrt(2))`


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`(42)/(2sqrt(3) + 3sqrt(2)`


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`(sqrt(3) + 1)/(sqrt(3) - 1)`


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`(sqrt(5) - sqrt(7))/sqrt(3)`


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`(2sqrt(3) - sqrt(6))/(2sqrt(3) + sqrt(6)`


Simplify the following

`(4 + sqrt(5))/(4 - sqrt(5)) + (4 - sqrt(5))/(4 + sqrt(5)`


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Evaluate, correct to one place of decimal, the expression `5/(sqrt20 - sqrt10)`, if `sqrt5` = 2.2 and `sqrt10` = 3.2.


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