हिंदी

Rationalize the denominator. 325-32

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प्रश्न

Rationalize the denominator.

`3/(2 sqrt 5 - 3 sqrt 2)`

योग
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उत्तर

`3/(2 sqrt 5 - 3 sqrt 2)`

`= 3/(2 sqrt 5 - 3 sqrt 2) xx (2 sqrt 5 + 3 sqrt 2)/(2 sqrt 5 + 3 sqrt 2)` 

`= (3(2 sqrt 5 + 3 sqrt 2))/((2 sqrt 5)^2 - (3 sqrt 2)^2)`

.....`[("a" + "b")("a" - "b") = "a"^2 - "b"^2]`

`= (3(2 sqrt 5 + 3 sqrt 2))/(4 xx 5 - 9 xx 2)`

`= (3(2 sqrt 5 + 3 sqrt 2))/(20 - 18)`

`= (3(2 sqrt 5 + 3 sqrt 2))/2`

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Simplifying an Expression by Rationalization of the Denominator
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Real Numbers - Practice Set 2.4 [पृष्ठ ३२]

APPEARS IN

बालभारती Mathematics 1 [English] Standard 9 Maharashtra State Board
अध्याय 2 Real Numbers
Practice Set 2.4 | Q (2) (ii) | पृष्ठ ३२

संबंधित प्रश्न

Rationalize the denominator.

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`(5)/(sqrt(7) - sqrt(2))`


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`(sqrt(7) - sqrt(5))/(sqrt(7) + sqrt(5)`


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Simplify by rationalising the denominator in the following.

`(7sqrt(3) -  5sqrt(2))/(sqrt(48) + sqrt(18)`


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`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`


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`(4sqrt(3))/((2 - sqrt(2))) - (30)/((4sqrt(3) - 3sqrt(2))) - (3sqrt(2))/((3 + 2sqrt(3))`


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`(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)) = "a" - "b"sqrt(6)`


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`x^2 + (1)/x^2`


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