Advertisements
Advertisements
प्रश्न
Rationalise the denominators of:
`[sqrt6 - sqrt5]/[sqrt6 + sqrt5]`
Advertisements
उत्तर
`[sqrt6 - sqrt5]/[sqrt6 + sqrt5] xx [sqrt6 - sqrt5]/[sqrt6 - sqrt5]`
= `[(sqrt6 - sqrt5)^2]/[(sqrt6)^2 - (sqrt5)^2]`
= `[(sqrt6)^2 + (sqrt5)^2 - 2(sqrt6 xx sqrt5)]/[(sqrt6)^2 - (sqrt5)^2]`
= `[6 + 5 - 2sqrt30 ]/[(sqrt6)^2 - (sqrt5)^2]`
= `[11 - 2sqrt30 ]/[6 - 5]`
= `11 - 2sqrt30`
APPEARS IN
संबंधित प्रश्न
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
If `sqrt2` = 1.4 and `sqrt3` = 1.7, find the value of `(2 - sqrt3)/(sqrt3).`
Simplify by rationalising the denominator in the following.
`(2)/(3 + sqrt(7)`
Simplify by rationalising the denominator in the following.
`(sqrt(3) + 1)/(sqrt(3) - 1)`
Simplify the following :
`(3sqrt(2))/(sqrt(6) - sqrt(3)) - (4sqrt(3))/(sqrt(6) - sqrt(2)) + (2sqrt(3))/(sqrt(6) + 2)`
In the following, find the values of a and b:
`(3 + sqrt(7))/(3 - sqrt(7)) = "a" + "b"sqrt(7)`
In the following, find the values of a and b:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = "a" - "b"sqrt(6)`
If x = `(7 + 4sqrt(3))`, find the value of
`sqrt(x) + (1)/(sqrt(x)`
If x = `((2 + sqrt(5)))/((2 - sqrt(5))` and y = `((2 - sqrt(5)))/((2 + sqrt(5))`, show that (x2 - y2) = `144sqrt(5)`.
Show that: `x^2 + 1/x^2 = 34,` if x = 3 + `2sqrt2`
