Advertisements
Advertisements
प्रश्न
Rationalise the denominators of : `[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ]`
Advertisements
उत्तर
`[ 2√5 + 3√2 ]/[ 2√5 - 3√2 ] xx [ 2√5 + 3√2 ]/[ 2√5 + 3√2 ]`
= `[( 2sqrt5 + 3sqrt2)^2]/[ (2sqrt5)^2 - (3sqrt2)^2]`
= `[ 4 xx 5 + 9 xx 2 + 12sqrt10 ]/[ 20 -18 ]`
= `[ 20 + 18 + 12sqrt10 ]/2`
= `[ 38 + 12sqrt10 ]/2`
= `[2( 19 + 6sqrt10 )]/2`
= 19 + 6√10
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
Rationalise the denominators of : `[ sqrt3 - sqrt2 ]/[ sqrt3 + sqrt2 ]`
Simplify by rationalising the denominator in the following.
`(sqrt(7) - sqrt(5))/(sqrt(7) + sqrt(5)`
Simplify by rationalising the denominator in the following.
`(3sqrt(5) + sqrt(7))/(3sqrt(5) - sqrt(7)`
In the following, find the value of a and b:
`(sqrt(3) - 1)/(sqrt(3) + 1) + (sqrt(3) + 1)/(sqrt(3) - 1) = "a" + "b"sqrt(3)`
If x = `(4 - sqrt(15))`, find the values of
`(1)/x`
If x = `(4 - sqrt(15))`, find the values of
`x^3 + (1)/x^3`
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Evaluate, correct to one place of decimal, the expression `5/(sqrt20 - sqrt10)`, if `sqrt5` = 2.2 and `sqrt10` = 3.2.
Show that: `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2) = 11`
