Advertisements
Advertisements
प्रश्न
In the following, find the values of a and b:
`(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)) = "a" - "b"sqrt(6)`
Advertisements
उत्तर
`(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)`
= `(7sqrt(3) - 5sqrt(2))/(4sqrt(3) + 3sqrt(2)) xx (4sqrt(3) - 3sqrt(2))/(4sqrt(3) - 3sqrt(2)`
= `(7sqrt(3)(4sqrt(3) - 3sqrt(2)) - 5sqrt(2)(4sqrt(3) - 3sqrt(2)))/((4sqrt(3))^2 - (3sqrt(2))^2`
= `(84 - 21sqrt(6) - 20sqrt(6) + 30)/(48 - 18)`
= `(110 - 41sqrt(6))/(30)`
= `(110)/(30) - (41sqrt(6))/(30)`
= `(11)/(3) - (41)/(30)sqrt(6)`
= `"a" - "b"sqrt(6)`
Hence, a = `(11)/(3)` and b = `(41)/(30)`.
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`12/(4sqrt3 - sqrt 2)`
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Rationalise the denominators of:
`[sqrt6 - sqrt5]/[sqrt6 + sqrt5]`
Simplify : `sqrt18/[ 5sqrt18 + 3sqrt72 - 2sqrt162]`
Simplify by rationalising the denominator in the following.
`(sqrt(7) - sqrt(5))/(sqrt(7) + sqrt(5)`
Simplify by rationalising the denominator in the following.
`(7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)`
Simplify the following
`(3)/(5 - sqrt(3)) + (2)/(5 + sqrt(3)`
In the following, find the values of a and b.
`(sqrt(3) - 1)/(sqrt(3) + 1) = "a" + "b"sqrt(3)`
Simplify:
`(sqrt(x^2 + y^2) - y)/(x - sqrt(x^2 - y^2)) ÷ (sqrt(x^2 - y^2) + x)/(sqrt(x^2 + y^2) + y)`
Draw a line segment of length `sqrt8` cm.
