Advertisements
Advertisements
प्रश्न
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
Advertisements
उत्तर
`[ 2 + sqrt3 ]/[ 2 - sqrt3 ] xx [ 2 + sqrt3 ]/[ 2 + sqrt3] = a + bsqrt3`
= `[ (2 + sqrt3)^2 ]/[ (2)^2 - (sqrt3)^2 ] = a + bsqrt3`
= `[ 4 + 3 + 4sqrt3]/[ 4 - 3 ] = a + bsqrt3`
7 + 4√3 = a + b√3
a = 7, b = 4
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`5/sqrt 7`
Write the lowest rationalising factor of : √18 - √50
Find the values of 'a' and 'b' in each of the following:
`( sqrt7 - 2 )/( sqrt7 + 2 ) = asqrt7 + b`
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find m2
Show that :
`1/[ 3 - 2√2] - 1/[ 2√2 - √7 ] + 1/[ √7 - √6 ] - 1/[ √6 - √5 ] + 1/[√5 - 2] = 5`
If `[ 2 + sqrt5 ]/[ 2 - sqrt5] = x and [2 - sqrt5 ]/[ 2 + sqrt5] = y`; find the value of x2 - y2.
Rationalise the denominator `1/sqrt(50)`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
Rationalise the denominator and simplify `sqrt(5)/(sqrt(6) + 2) - sqrt(5)/(sqrt(6) - 2)`
