Advertisements
Advertisements
प्रश्न
Rationalise the denominators of:
`[sqrt6 - sqrt5]/[sqrt6 + sqrt5]`
Advertisements
उत्तर
`[sqrt6 - sqrt5]/[sqrt6 + sqrt5] xx [sqrt6 - sqrt5]/[sqrt6 - sqrt5]`
= `[(sqrt6 - sqrt5)^2]/[(sqrt6)^2 - (sqrt5)^2]`
= `[(sqrt6)^2 + (sqrt5)^2 - 2(sqrt6 xx sqrt5)]/[(sqrt6)^2 - (sqrt5)^2]`
= `[6 + 5 - 2sqrt30 ]/[(sqrt6)^2 - (sqrt5)^2]`
= `[11 - 2sqrt30 ]/[6 - 5]`
= `11 - 2sqrt30`
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
Rationalise the denominators of : `1/(sqrt3 - sqrt2 )`
Rationalise the denominators of : `3/[ sqrt5 + sqrt2 ]`
Simplify : `sqrt18/[ 5sqrt18 + 3sqrt72 - 2sqrt162]`
Simplify by rationalising the denominator in the following.
`(3sqrt(2))/sqrt(5)`
Simplify by rationalising the denominator in the following.
`(2)/(3 + sqrt(7)`
Simplify by rationalising the denominator in the following.
`(sqrt(3) + 1)/(sqrt(3) - 1)`
Simplify by rationalising the denominator in the following.
`(3 - sqrt(3))/(2 + sqrt(2)`
Simplify by rationalising the denominator in the following.
`(sqrt(12) + sqrt(18))/(sqrt(75) - sqrt(50)`
Simplify the following
`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`
