Advertisements
Advertisements
प्रश्न
Show that: `(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2) = 11`
Advertisements
उत्तर
`(3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) + (2 sqrt3)/(sqrt3 - sqrt2)`
`=> (3sqrt2 - 2sqrt3)/(3sqrt2 + 2sqrt3) xx (3sqrt2 - 2sqrt3)/(3sqrt2 - 2sqrt3) + (2sqrt3)/(sqrt3 - sqrt2) xx (sqrt3 + sqrt2)/(sqrt3 + sqrt2)`
`=> ((3sqrt2 - 2sqrt3)^2)/((3sqrt2)^2 - (2sqrt3)^2) + (2sqrt3 (sqrt3 + sqrt2))/((sqrt3)^2 - (sqrt2)^2)`
`=> ((3sqrt2)^2 + (2sqrt3)^2 - 2 xx 3sqrt2 xx 2sqrt3)/((9 xx 2) - (4 xx 3)) + (6 + 2sqrt6)/(3 - 2)`
`=> (18 + 12 - 12sqrt6)/(18 - 12) + 6 + 2sqrt6`
`=> (30 - 12sqrt6)/6 + 6 + 2sqrt6`
`=> (cancel(6) (5 - 2sqrt6))/cancel(6) + 6 + 2sqrt6`
`=> 5 - cancel(2sqrt6) + 6 + cancel(2sqrt6)`
= 5 + 6
= 11
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`3/(2 sqrt 5 - 3 sqrt 2)`
Rationalize the denominator.
`1/sqrt5`
Rationalize the denominator.
`1/(3 sqrt 5 + 2 sqrt 2)`
Rationalise the denominators of : `3/sqrt5`
Simplify by rationalising the denominator in the following.
`(2)/(3 + sqrt(7)`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify by rationalising the denominator in the following.
`(3sqrt(5) + sqrt(7))/(3sqrt(5) - sqrt(7)`
Simplify the following :
`(6)/(2sqrt(3) - sqrt(6)) + sqrt(6)/(sqrt(3) + sqrt(2)) - (4sqrt(3))/(sqrt(6) - sqrt(2)`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x3 + y3
Using the following figure, show that BD = `sqrtx`.

