Advertisements
Advertisements
Question
Simplify by rationalising the denominator in the following.
`(sqrt(5) - sqrt(7))/sqrt(3)`
Advertisements
Solution
`(sqrt(5) - sqrt(7))/sqrt(3)`
= `(sqrt(5) - sqrt(7))/sqrt(3) xx sqrt(3)/sqrt(3)`
= `(sqrt(5) xx sqrt(3) - sqrt(7) xx sqrt(3))/(sqrt(3))^2`
= `(sqrt(15) - sqrt(21))/(3)`
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`1/(sqrt 7 + sqrt 2)`
Rationalize the denominator.
`1/sqrt5`
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Simplify:
`sqrt2/[sqrt6 - sqrt2] - sqrt3/[sqrt6 + sqrt2]`
Simplify the following
`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`
Simplify the following
`(sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3)) + (sqrt(5) - sqrt(3))/(sqrt(5) + sqrt(3)`
Simplify the following :
`(6)/(2sqrt(3) - sqrt(6)) + sqrt(6)/(sqrt(3) + sqrt(2)) - (4sqrt(3))/(sqrt(6) - sqrt(2)`
In the following, find the values of a and b:
`(sqrt(3) - 2)/(sqrt(3) + 2) = "a"sqrt(3) + "b"`
If x = `(7 + 4sqrt(3))`, find the values of :
`(x + (1)/x)^2`
Using the following figure, show that BD = `sqrtx`.
