Advertisements
Advertisements
Question
Rationalise the denominators of : `[ √3 + 1 ]/[ √3 - 1 ]`
Advertisements
Solution
= `[ √3 + 1 ]/[ √3 - 1 ] xx [ √3 + 1 ]/[ √3 + 1 ]`
= `[( √3 + 1 )^2]/[( √3 )^2 - (1)^2 ]`
= `[ 3 + 1 + 2√3 ]/[ 3 - 1]`
= `[ 4 + 2√3 ]/[2]`
= `[ 2( 2 + √3 )]/[ 2 ]`
= 2 + √3
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`1/(sqrt 7 + sqrt 2)`
Rationalize the denominator.
`(sqrt 5 - sqrt 3)/(sqrt 5 + sqrt 3)`
If `sqrt2` = 1.4 and `sqrt3` = 1.7, find the value of `(2 - sqrt3)/(sqrt3).`
Simplify by rationalising the denominator in the following.
`(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6)`
Simplify by rationalising the denominator in the following.
`(7sqrt(3) - 5sqrt(2))/(sqrt(48) + sqrt(18)`
Simplify the following
`(sqrt(7) - sqrt(3))/(sqrt(7) + sqrt(3)) - (sqrt(7) + sqrt(3))/(sqrt(7) - sqrt(3)`
In the following, find the value of a and b:
`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = "a" + "b"sqrt(5)`
If x = `(7 + 4sqrt(3))`, find the values of :
`(x + (1)/x)^2`
Draw a line segment of length `sqrt5` cm.
Using the following figure, show that BD = `sqrtx`.
