Advertisements
Advertisements
Question
Rationalise the denominators of : `[ √3 + 1 ]/[ √3 - 1 ]`
Advertisements
Solution
= `[ √3 + 1 ]/[ √3 - 1 ] xx [ √3 + 1 ]/[ √3 + 1 ]`
= `[( √3 + 1 )^2]/[( √3 )^2 - (1)^2 ]`
= `[ 3 + 1 + 2√3 ]/[ 3 - 1]`
= `[ 4 + 2√3 ]/[2]`
= `[ 2( 2 + √3 )]/[ 2 ]`
= 2 + √3
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`1/sqrt5`
Simplify : `sqrt18/[ 5sqrt18 + 3sqrt72 - 2sqrt162]`
Simplify by rationalising the denominator in the following.
`(sqrt(5) - sqrt(7))/sqrt(3)`
Simplify by rationalising the denominator in the following.
`(3 - sqrt(3))/(2 + sqrt(2)`
Simplify by rationalising the denominator in the following.
`(5 + sqrt(6))/(5 - sqrt(6)`
Simplify by rationalising the denominator in the following.
`(sqrt(15) + 3)/(sqrt(15) - 3)`
Simplify the following
`(4 + sqrt(5))/(4 - sqrt(5)) + (4 - sqrt(5))/(4 + sqrt(5)`
If x = `((sqrt(3) + 1))/((sqrt(3) - 1)` and y = `((sqrt(3) - 1))/((sqrt(3) + 1)`, find the values of
x3 + y3
If x = `(1)/((3 - 2sqrt(2))` and y = `(1)/((3 + 2sqrt(2))`, find the values of
x3 + y3
Using the following figure, show that BD = `sqrtx`.
