Advertisements
Advertisements
प्रश्न
Simplify:
`sqrt2/[sqrt6 - sqrt2] - sqrt3/[sqrt6 + sqrt2]`
Advertisements
उत्तर
`sqrt2/[sqrt6 - sqrt2] - sqrt3/[sqrt6 + sqrt2]`
= `[ sqrt2]/[ sqrt6 - 2] - [ sqrt3 ]/[ sqrt6 + sqrt2 ] `
`= [ sqrt2( sqrt6 + sqrt2) - sqrt3( sqrt6 - sqrt2 )]/[ (sqrt6 - sqrt2)- (sqrt 6 + sqrt2)]`
= `[ sqrt12 + 2 - sqrt18 + sqrt6 ]/[ (sqrt6)^2 - (sqrt2)^2 ]`
= `[ 2sqrt3 + 2 - 3sqrt2 + sqrt6 ]/(6 - 2)`
= `[ 2sqrt3 + 2 - 3sqrt2 + sqrt6 ]/4`
APPEARS IN
संबंधित प्रश्न
Rationalise the denominators of : `(2sqrt3)/sqrt5`
Simplify by rationalising the denominator in the following.
`(1)/(sqrt(3) + sqrt(2))`
Simplify by rationalising the denominator in the following.
`(5)/(sqrt(7) - sqrt(2))`
Simplify by rationalising the denominator in the following.
`(2sqrt(3) - sqrt(6))/(2sqrt(3) + sqrt(6)`
Simplify the following
`(4 + sqrt(5))/(4 - sqrt(5)) + (4 - sqrt(5))/(4 + sqrt(5)`
Simplify the following :
`(6)/(2sqrt(3) - sqrt(6)) + sqrt(6)/(sqrt(3) + sqrt(2)) - (4sqrt(3))/(sqrt(6) - sqrt(2)`
In the following, find the values of a and b:
`(1)/(sqrt(5) - sqrt(3)) = "a"sqrt(5) - "b"sqrt(3)`
In the following, find the values of a and b:
`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = "a" - "b"sqrt(6)`
If x = `(4 - sqrt(15))`, find the values of
`x + (1)/x`
Show that: `x^2 + 1/x^2 = 34,` if x = 3 + `2sqrt2`
