Advertisements
Advertisements
Question
If m = `1/[ 3 - 2sqrt2 ] and n = 1/[ 3 + 2sqrt2 ],` find mn
Sum
Advertisements
Solution
mn = ( 3 + 2√2 )( 3 - 2√2 )
= (3)2 - (2√2)2
= 9 - 8
= 1
shaalaa.com
Rationalisation of Surds
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Rationalize the denominator.
`3 /sqrt5`
Rationalize the denominator.
`1/sqrt14`
Write the lowest rationalising factor of 5√2.
Write the lowest rationalising factor of √5 - 3.
Write the lowest rationalising factor of : 7 - √7
Write the lowest rationalising factor of : √13 + 3
Write the lowest rationalising factor of 15 – 3√2.
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If x = 2√3 + 2√2, find: `(x + 1/x)`
Rationalise the denominator and simplify `(2sqrt(6) - sqrt(5))/(3sqrt(5) - 2sqrt(6))`
