Advertisements
Advertisements
प्रश्न
Find the values of 'a' and 'b' in each of the following:
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
Advertisements
उत्तर
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
`3/[ sqrt3 - sqrt2 ] xx [ sqrt3 + sqrt2 ]/[ sqrt3 + sqrt2 ]= asqrt3 - bsqrt2`
`(3sqrt3 + 3sqrt2)/ ((sqrt3^2) - (sqrt2^2)) = asqrt3 - bsqrt2`
`(3sqrt3 + 3sqrt2) / (3-2) = asqrt3 - bsqrt2`
`(3sqrt3 + 3sqrt2)/1 = asqrt3 - bsqrt2`
`a = sqrt3 - bsqrt2 = 3sqrt3 + 3sqrt2`
∴ a= 3 and b= -3
APPEARS IN
संबंधित प्रश्न
Write the simplest form of rationalising factor for the given surd.
`sqrt 32`
Write the simplest form of rationalising factor for the given surd.
`3/5 sqrt 10`
Write the lowest rationalising factor of 5√2.
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find : xy
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If x = 2√3 + 2√2, find: `(x + 1/x)`
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
Rationalise the denominator `1/sqrt(50)`
Find the value of a and b if `(sqrt(7) - 2)/(sqrt(7) + 2) = asqrt(7) + b`.
If x = `sqrt(5) + 2`, then find the value of `x^2 + 1/x^2`
