Advertisements
Advertisements
प्रश्न
Find the values of 'a' and 'b' in each of the following:
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
Advertisements
उत्तर
`3/[ sqrt3 - sqrt2 ] = asqrt3 - bsqrt2`
`3/[ sqrt3 - sqrt2 ] xx [ sqrt3 + sqrt2 ]/[ sqrt3 + sqrt2 ]= asqrt3 - bsqrt2`
`(3sqrt3 + 3sqrt2)/ ((sqrt3^2) - (sqrt2^2)) = asqrt3 - bsqrt2`
`(3sqrt3 + 3sqrt2) / (3-2) = asqrt3 - bsqrt2`
`(3sqrt3 + 3sqrt2)/1 = asqrt3 - bsqrt2`
`a = sqrt3 - bsqrt2 = 3sqrt3 + 3sqrt2`
∴ a= 3 and b= -3
APPEARS IN
संबंधित प्रश्न
Rationalize the denominator.
`11 / sqrt 3`
Find the values of 'a' and 'b' in each of the following :
`[2 + sqrt3]/[ 2 - sqrt3 ] = a + bsqrt3`
Find the values of 'a' and 'b' in each of the following:
`[5 + 3sqrt2]/[ 5 - 3sqrt2] = a + bsqrt2`
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2 ]`; find : xy
If x =`[sqrt5 - 2 ]/[ sqrt5 + 2]` and y = `[ sqrt5 + 2]/[ sqrt5 - 2]`; find:
x2 + y2 + xy.
If x = 2√3 + 2√2 , find : `( x + 1/x)^2`
If x = 5 - 2√6, find `x^2 + 1/x^2`
Rationalise the denominator `sqrt(75)/sqrt(18)`
Rationalise the denominator and simplify `(sqrt(48) + sqrt(32))/(sqrt(27) - sqrt(18))`
Find the value of a and b if `(sqrt(7) - 2)/(sqrt(7) + 2) = asqrt(7) + b`.
