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Planes Are Drawn Through the Points (5, 0, 2) and (3, –2, 5) Parallel to the Coordinate Planes. Find the Lengths of the Edges of the Rectangular Parallelepiped So Formed. - Mathematics

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प्रश्न

Planes are drawn through the points (5, 0, 2) and (3, –2, 5) parallel to the coordinate planes. Find the lengths of the edges of the rectangular parallelepiped so formed. 

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उत्तर

Clearly, PBEC and QDAF are the planes parallel to the yz-plane such that their distances from the yz-plane are 5 and 3, respectively. 

\[\therefore\]PA = Distance between planes PBEC and QDAF
           = 5\[-\]3

            = 2 

PB is the distance between planes PAFC and BDQE that are parallel to the zx-plane and are at distances 0 and\[-\]2,respectively, from the zx-plane.

\[\therefore\]PB = 0

\[-\](\[-\]2)
   = 2

PC is the distance between parallel planes PBDA and CEQF that are at distances 2 and 5, respectively, from the xy-plane.

\[\therefore\]PC = 2\[-\]5

  =\[-\]3

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अध्याय 28: Introduction to three dimensional coordinate geometry - Exercise 15.1 [पृष्ठ ७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 28 Introduction to three dimensional coordinate geometry
Exercise 15.1 | Q 5 | पृष्ठ ७

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