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In ∆Abc, If Sin2 a + Sin2 B = Sin2 C. Show that the Triangle is Right-angled. - Mathematics

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प्रश्न

In ∆ABC, if sin2 A + sin2 B = sin2 C. show that the triangle is right-angled. 

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उत्तर

In ∆ ABC,
Given, \[\sin^2 A + \sin^2 B = \sin^2 C . . . . . . \left( 1 \right)\] 

Suppose 

\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = k\]

⇒ \[\sin A = \frac{a}{k}, \sin B = \frac{b}{k}, \sin C = \frac{c}{k}\] 

On putting these values in equation (1), we get: 

\[\frac{a^2}{k^2} + \frac{b^2}{k^2} = \frac{c^2}{k^2} \Rightarrow a^2 + b^2 = c^2\] 

Thus, ∆ ABC is right-angled. 

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Sine and Cosine Formulae and Their Applications
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Sine and cosine formulae and their applications - Exercise 10.1 [पृष्ठ १३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 10 Sine and cosine formulae and their applications
Exercise 10.1 | Q 26 | पृष्ठ १३

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