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If ω is a complex cube root of unity, find the value of ω2 + ω3 + ω4

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प्रश्न

If ω is a complex cube root of unity, find the value of ω2 + ω3 + ω4

योग
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उत्तर

Since ω is the complex cube root of unity,

ω3 = 1 and 1 + ω + ω2 = 0

∴  1 + ω = – ω2, 1 + ω2 = – ω and ω + ω2 = – 1.

ω2 + ω3 + ω4 = ω2(1 + ω + ω2)

= ω2 × 0

= 0

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अध्याय 1: Complex Numbers - Exercise 1.4 [पृष्ठ २०]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 1 Complex Numbers
Exercise 1.4 | Q 3. (ii) | पृष्ठ २०

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