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If ω is a complex cube root of unity, find the value of ω+1ω

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प्रश्न

If ω is a complex cube root of unity, find the value of `omega + 1/omega`

योग
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उत्तर

ω is a complex cube root of unity
∴ ω3 = 1 and 1 + ω + ω2 = 0

Also, 1 + ω2 = - ω, 1 + ω = -  ω2 and ω + ω2 = – 1

`omega + 1/omega = (omega^2 + 1)/omega = (-omega)/omega` = – 1.

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अध्याय 3: Complex Numbers - EXERCISE 3.3 [पृष्ठ ४२]

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बालभारती Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 3 Complex Numbers
EXERCISE 3.3 | Q 2) i) | पृष्ठ ४२

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