हिंदी

If α and β are complex cube roots of unity, prove that (1 − α)(1 − β) (1 − α2)(1 − β2) = 9.

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प्रश्न

If α and β are complex cube roots of unity, prove that (1 − α)(1 − β) (1 − α2)(1 − β2) = 9.

योग
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उत्तर

Since α and β are the complex cube roots of unity, α2 = β and β2 = α

Also, α3 = 1, 1 + α + α2 = 0

∴ α4 = α3.α = α, 1 + α2 = – α and 1 + α = – α2

∴ (1 – α)(1 – β)(1 – α2)(1 – β2)

= (1 – α)(1 – α2)(1 – α2)(1 – α)

= (1 – α)2(1 – α2)2

= (1 + α2 – 2α)(1 + α4 – 2α2)

= (1 + α2 – 2α)(1 + α – 2α2)        ...[∵ α4 = α]

= (– α – 2α)(– α2 – 2α2)

= (– 3α)(– 3α2)

= 9 α3

= 9 × 1

= 9

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Complex Numbers - Miscellaneous Exercise 1.2 [पृष्ठ २२]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 1 Complex Numbers
Miscellaneous Exercise 1.2 | Q II.18 | पृष्ठ २२

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