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If ЁЭЬФ is a complex cube root of unity, find the value of (1+ЁЭЬФ)тБв(1+ЁЭЬФ2)тБв(1+ЁЭЬФ4)тБв(1+ЁЭЬФ8) - Mathematics and Statistics

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If `omega` is a complex cube root of unity, find the value of `(1 + omega)(1 + omega^2)(1 + omega^4)(1 + omega^8)`

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ω is a complex cube root of unity

∴ ω3 = 1 and 1 + ω + ω2 = 0

Also, 1 + ω2 = -ω, 1 + ω = -ω2 and ω + ω2 = –1

(1 + ω)(1 + ω2)(1 + ω4)(1 + ω8)

= (1 + ω)(1 + ω2)(1 + ω)(1 + ω2)        ...[тИ╡ ω3 = 1, ∴ ω4 = ω]

= (- ω2) (- ω) (- ω2) (- ω)

= ω6

= (ω3)2

= (1)2  

= 1

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Cube Root of Unity
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рдЕрдзреНрдпрд╛рдп 3: Complex Numbers - EXERCISE 3.3 [рдкреГрд╖реНрда рекреи]

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рдмрд╛рд▓рднрд╛рд░рддреА Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
рдЕрдзреНрдпрд╛рдп 3 Complex Numbers
EXERCISE 3.3 | Q 2) v) | рдкреГрд╖реНрда рекреи

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