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प्रश्न
Select the correct answer from the given alternatives:
If ω is a complex cube root of unity, then the value of ω99+ ω100 + ω101 is :
विकल्प
−1
1
0
3
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उत्तर
0
Explanation:
ω99+ ω100 + ω101
= ω99 (1 + ω + ω2)
= ω99 (0)
= 0
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