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If ω is a complex cube root of unity, find the value of (1+ω2)3

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प्रश्न

If ω is a complex cube root of unity, find the value of (1 + ω2)3

योग
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उत्तर

ω is a complex cube root of unity
∴ ω3 = 1 and 1 + ω + ω2 = 0

Also, 1 + ω2 = - ω, 1 + ω = -  ω2 and ω + ω2 = – 1

(1 + ω2)= (- ω)3 = - ω3 = - 1

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Complex Numbers - EXERCISE 3.3 [पृष्ठ ४२]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
अध्याय 3 Complex Numbers
EXERCISE 3.3 | Q 2) iii) | पृष्ठ ४२

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