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If ω is a complex cube root of unity, find the value of (1 + ω2)3

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प्रश्न

If ω is a complex cube root of unity, find the value of (1 + ω2)3

योग
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उत्तर

ω is the complex cube root of unity

∴ ω3 = 1 and 1 + ω + ω2 = 0

Also, 1 + ω2 = – ω, 1 + ω = – ω2 and ω + ω2 = – 1

(1 + ω2)3

= (– ω)3

= – ω3

= –1

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अध्याय 1: Complex Numbers - Exercise 1.4 [पृष्ठ २०]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 1 Complex Numbers
Exercise 1.4 | Q 3. (iii) | पृष्ठ २०

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