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If ω is a complex cube root of unity, find the value of (1 + ω2)3

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Question

If ω is a complex cube root of unity, find the value of (1 + ω2)3

Sum
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Solution

ω is the complex cube root of unity

∴ ω3 = 1 and 1 + ω + ω2 = 0

Also, 1 + ω2 = – ω, 1 + ω = – ω2 and ω + ω2 = – 1

(1 + ω2)3

= (– ω)3

= – ω3

= –1

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Chapter 1: Complex Numbers - Exercise 1.4 [Page 20]

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