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If ω is a complex cube root of unity, find the value of ω2 + ω3 + ω4

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प्रश्न

If ω is a complex cube root of unity, find the value of ω2 + ω3 + ω4

बेरीज
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उत्तर

Since ω is the complex cube root of unity,

ω3 = 1 and 1 + ω + ω2 = 0

∴  1 + ω = – ω2, 1 + ω2 = – ω and ω + ω2 = – 1.

ω2 + ω3 + ω4 = ω2(1 + ω + ω2)

= ω2 × 0

= 0

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Complex Numbers - Exercise 1.4 [पृष्ठ २०]

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