मराठी

If x = a + b, y = αa + βb and z = aβ + bα, where α and β are the complex cube roots of unity, show that xyz = a3 + b3.

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प्रश्न

If x = a + b, y = αa + βb and z = aβ + bα, where α and β are the complex cube roots of unity, show that xyz = a3 + b3.

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उत्तर

x = a + b, y = αa + βb and z = aβ + bα
α and β are the complex cube roots of unity.

∴ α = `(-1 + "i"sqrt(3))/2 and beta = (-1 - "i"sqrt(3))/2`

∴ αβ = `((-1 + "i"sqrt(3))/2)((-1 - "i"sqrt(3))/2)`

= `((-1)^2 - ("i"sqrt(3))^2)/4`

= `(1 - (-1)(3))/4`         ...[∵ i2 = – 1]

= `(1 + 3)/4`

∴ αβ = 1

Also, α + β = `(-1 + "i"sqrt(3))/2 + (-1 - "i"sqrt(3))/2`

= `(-1 + "i"sqrt(3) - 1 - "i"sqrt(3))/2` 

= `(-2)/2`

∴ α + β = -1
L.H.S. = xyz = (a + b)(αa + βb)(aβ + bα)
= (a + b)(αβa2 + α2ab + β2ab + αβb2)
= (a + b)[1. (a2) + (α2 + β2)ab + 1. (b2)]
= (a + b) {a2 + [(α + β)2 – 2αβ ]ab + b2}
= (a + b) {a2 + [(– 1)2 – 2(1)]ab + b2}
= (a + b) [a2 + (1 – 2)ab + b2]
= (a + b)(a2 – ab + b2)
= a3 +b3
= R.H.S.

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पाठ 3: Complex Numbers - EXERCISE 3.3 [पृष्ठ ४२]

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