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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How much charge is required for the following reduction? 1 mol of MnO⁢4- to Mn2+.

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प्रश्न

How much charge is required for the following reduction? 

1 mol of \[\ce{MnO^-_4}\] to Mn2+.

संख्यात्मक
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उत्तर

The given reaction is:

\[\ce{\underset{(1 mol)}{MnO^-_4} + 8H^+ + \underset{(5 mol)}{5e^-} -> Mn^{2+} + 4H2O}\]

∴ 5 mole electrons are needed for the reduction of 1 mole of \[\ce{MnO^-_4}\] to Mn2+.

∴ 5 mole electrons = 5 Faradays

= 5 × 96500 C

= 4.825 × 105 C

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अध्याय 2: Electrochemistry - Exercises [पृष्ठ ६०]

APPEARS IN

एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 2 Electrochemistry
Exercises | Q 2.12 (iii) | पृष्ठ ६०
नूतन Chemistry [English] Class 12 ISC
अध्याय 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.12 (iii) | पृष्ठ २११

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