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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How much charge is required for the following reduction? 1 mol of Al3+ to Al.

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प्रश्न

How much charge is required for the following reduction?

1 mol of Al3+ to Al.

संख्यात्मक
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उत्तर

The given reaction is:

\[\ce{\underset{(1 mol)}{Al^{3+}} + \underset{(3 mol)}{3e-} -> Al}\]

∴ 3 moles of electrons are needed for the reduction of 1 mole of Al3+ to Al.

3 mole electrons = 3 Faradays

= 3 × 96500 C

= 2.895 × 105 C

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Electrochemistry - Exercises [पृष्ठ ६०]

APPEARS IN

एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 2 Electrochemistry
Exercises | Q 2.12 (i) | पृष्ठ ६०
नूतन Chemistry [English] Class 12 ISC
अध्याय 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.12 (i) | पृष्ठ २११

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