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A solution of Ni(NO3)2 is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode?

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प्रश्न

A solution of Ni(NO3)2 is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode?

संख्यात्मक
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उत्तर

Given: Current (I) = 5 A

Time (t) = 20 min = 20 × 60 = 1200 sec

Atomic weight of Ni = 58.70

The reaction takes place in the following manner:

\[\ce{Ni^{2+} + 2e- -> Ni}\]

Equivalent weight of Ni = \[\ce{\frac{Atomic weight}{Number of valence electrons}}\]

= \[\ce{\frac{58.70}{2}}\]

= 29.35

According to Faraday’s first law of electrolysis,

W = Z I t

= \[\ce{\frac{Equivalent weight}{96500} \times I \times t}\]

= \[\ce{\frac{29.35}{96500} \times 5 \times 1200}\]

= 1.825 g

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अध्याय 2: Electrochemistry - Exercises [पृष्ठ ६०]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 2 Electrochemistry
Exercises | Q 2.15 | पृष्ठ ६०
नूतन Chemistry [English] Class 12 ISC
अध्याय 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.15 | पृष्ठ २१२

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