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A solution of Ni(NO3)2 is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode? - Chemistry

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प्रश्न

A solution of Ni(NO3)2 is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode?

संख्यात्मक
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उत्तर

The reaction takes place in the following manner:

\[\ce{Ni^{2+} + 2e- -> Ni}\]

Atomic weight of \[\ce{Ni}\] = 58.70

Equivalent weight of Ni = \[\ce{\frac{Atomic weight}{Number of valence electrons}}\]

= \[\ce{\frac{58.70}{2}}\]

= 29.35

According to Faraday’s first law of electrolysis,

\[\ce{W = Z . I . t = \frac{Equivalent weight}{96500} \times I \times t}\]

= \[\ce{\frac{29.35}{96500} × 5 \times 20 \times 60}\]

= 1.825 g

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अध्याय 2: Electrochemistry - Exercises [पृष्ठ ६०]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 2 Electrochemistry
Exercises | Q 2.15 | पृष्ठ ६०

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