Question

Given `1/a` = 0.5 CM^–1, R = 50 ohm, N = 1.0 then equivalent conductance of electrolytic cell is

विकल्प

• 10 ohm^–1 cm² (gm equir^–1)

• 20 ohm^–1 cm² (gm equir^–1)

• 300 ohm^–1 cm² (gm equir^–1)

• 100 ohm^–1 cm² (gm equir^–1)

Answer 1

10 ohm^–1 cm² (gm equir^–1)

Explanation:

`K = 1/a xx 1/R = (0.5  CM - 1) xx (1/50  ohm^-1)`

= 0.01 ohm^–1 cm^–1 

E = `(K xx 100)/N = ((0.01  ohm^-1  cm^-1) xx (1000  cm^3))/(1  gm  "equivalemt")`

= `10   ohm^-1  cm^2  g/"equivalent"`