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Find the eccentricity of an ellipse, if the length of its latus rectum is one-third of its minor axis.

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प्रश्न

Find the eccentricity of an ellipse, if the length of its latus rectum is one-third of its minor axis.

योग
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उत्तर

Let the equation of the ellipse be

`x^2/"a"^2 + y^2/"b"^2` = 1

It is given that,

l(LR) = `1/3l("minor axis")`

∴ `(2"b"^2)/"a" = 1/3(2"b")`

∴ 3b = a

∴ 9b2 = a2

∴ 9a2(1 – e2) = a2

∴ 9(1 – e2) = 1

∴ 9 – 9e2 = 1

∴ 8 = 9e2

∴ e2 = `8/9`

∴ e = `(2sqrt(2))/3` ... [∵ 0 < e < 1]

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अध्याय 7: Conic Sections - Exercise 7.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Exercise 7.2 | Q 3 | पृष्ठ १६३

संबंधित प्रश्न

Answer the following:

Find the

  1. lengths of the principal axes
  2. co-ordinates of the foci
  3. equations of directrices
  4. length of the latus rectum
  5. distance between foci
  6. distance between directrices of the ellipse:

`x^2/25 + y^2/9` = 1


Find the

  1. lengths of the principal axes.
  2. co-ordinates of the focii 
  3. equations of directrics 
  4. length of the latus rectum
  5. distance between focii 
  6. distance between directrices of the ellipse:

2x2 + 6y2 = 6


Find the 

  1. lengths of the principal axes. 
  2. co-ordinates of the focii 
  3. equations of directrices 
  4. length of the latus rectum
  5. distance between focii 
  6. distance between directrices of the ellipse:

3x2 + 4y2 = 1


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