हिंदी

Find the equation of the ellipse in standard form if the distance between directrix is 18 and eccentricity is 13.

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प्रश्न

Find the equation of the ellipse in standard form if the distance between directrix is 18 and eccentricity is `1/3`.

योग
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उत्तर

Let the required equation of ellipse be

`x^2/"a"^2 + y^2/"b"^2` = 1, where a > b.

Given, eccentricity (e) = `1/3`

Distance between directrices = `(2"a")/"e"`

Given, distance between directrices = 18

∴ `(2"a")/"e"` = 18

∴ `(2"a")/(1/3)` = 18

∴ 6a = 18

∴ a = `18/6` = 3

∴ a2 = 9

Now, b2 = a2 (1 – e2)

= `9[1 - (1/3)^2]`

= `9(1 - 1/9)`

= `9(8/9)`

= 8

∴ The required equation of ellipse is `x^2/9 + y^2/8` = 1.

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अध्याय 7: Conic Sections - Exercise 7.2 [पृष्ठ १६३]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 7 Conic Sections
Exercise 7.2 | Q 2. (iii) | पृष्ठ १६३

संबंधित प्रश्न

Answer the following:

Find the

  1. lengths of the principal axes
  2. co-ordinates of the foci
  3. equations of directrices
  4. length of the latus rectum
  5. distance between foci
  6. distance between directrices of the ellipse:

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Find the

  1. lengths of the principal axes.
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  3. equations of directrics
  4. length of the latus rectum
  5. distance between focii
  6. distance between directrices of the ellipse:

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  3. equations of directrics 
  4. length of the latus rectum
  5. distance between focii 
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